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Calculate the pressure exerted by 10^(23...

Calculate the pressure exerted by `10^(23)` gas particles each of mass `10^(- 22)` g in a container of volume `1 dm^(3)`. The root mean square speed is `10^(5) cms^(- 1)`

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To calculate the pressure exerted by \(10^{23}\) gas particles, each with a mass of \(10^{-22}\) g, in a container of volume \(1 \, \text{dm}^3\) with a root mean square speed of \(10^{5} \, \text{cm/s}\), we can follow these steps: ### Step 1: Convert Mass to Kilograms The mass of each gas particle is given as \(10^{-22} \, \text{g}\). To convert this to kilograms: \[ \text{mass} = 10^{-22} \, \text{g} \times \frac{1 \, \text{kg}}{1000 \, \text{g}} = 10^{-25} \, \text{kg} \] ...
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