The ratio of the root mean square velocity of `H_(2)` at `50 K` to that of `O_(2)` at `800K` is

Options

A. 4
B. 2
C. 1
D. `(1)/(4)`

Answer

C

Explanation

`u_(rms)=sqrt((3RT)/(M)), u_("rms") prop sqrt((T)/(M))` `(u_('rms")(H_(2) " " at " " 50 K))/(u_("rms")(O_(2)" " at" " 800 K))= sqrt((50)/(2) xx (32)/(800))=1`