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300 ml of a gas at 300 K is cooled to 27...

300 ml of a gas at 300 K is cooled to 276 K at constant pressure. The final volume is

A

540 ml

B

276 ml

C

350 ml

D

135 ml

Text Solution

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The correct Answer is:
To solve the problem of finding the final volume of a gas when it is cooled at constant pressure, we can use the relationship derived from the ideal gas law. Here’s a step-by-step solution: ### Step 1: Write down the initial conditions - Initial volume (V1) = 300 ml - Initial temperature (T1) = 300 K ### Step 2: Write down the final conditions - Final temperature (T2) = 276 K - Final volume (V2) = ? ### Step 3: Use the formula for constant pressure Since the pressure is constant, we can use the relationship: \[ \frac{V1}{T1} = \frac{V2}{T2} \] ### Step 4: Substitute the known values into the equation Substituting the known values into the equation: \[ \frac{300 \, \text{ml}}{300 \, \text{K}} = \frac{V2}{276 \, \text{K}} \] ### Step 5: Cross-multiply to solve for V2 Cross-multiplying gives: \[ V2 = \frac{300 \, \text{ml} \times 276 \, \text{K}}{300 \, \text{K}} \] ### Step 6: Simplify the equation The 300 K in the numerator and denominator cancels out: \[ V2 = 276 \, \text{ml} \] ### Step 7: State the final answer The final volume (V2) of the gas when cooled to 276 K at constant pressure is **276 ml**. ---

To solve the problem of finding the final volume of a gas when it is cooled at constant pressure, we can use the relationship derived from the ideal gas law. Here’s a step-by-step solution: ### Step 1: Write down the initial conditions - Initial volume (V1) = 300 ml - Initial temperature (T1) = 300 K ### Step 2: Write down the final conditions - Final temperature (T2) = 276 K ...
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