If the rate of diffusion of gas X (Molecular mass 64 amu) is 1.4 times the rate of diffusion of gas Y at the same pressure then the molecular mass of gas Y is? 

Explanation

To find the molecular mass of gas Y, we can use Graham's law of diffusion, which states that the rate of diffusion of a gas is inversely proportional to the square root of its molar mass. The formula can be expressed as:

\[ \frac{r_X}{r_Y} = \sqrt{\frac{M_Y}{M_X}} \]

Where:
- \( r_X \) = rate of diffusion of gas X
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