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16 g of O(2) gas at STP is expanded so t...

16 g of `O_(2)` gas at STP is expanded so that volume is doubled. Hence, work done is

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Number of molec of `O_(2)=8//32=0.25` mol and at S.T.P. one mole `O_(2)` occupies = 22.4 litre.
`therefore 0.25` mole of `O_(2)` occupies, i.e., `V_(i)=0.25xx22.4=5.6` litre
Here, `V_(f)=2V_(i)=2xx5.6=11.2 L` (given) `rArr =11.2-5.6 =5.6 L`
`W=-P Delta V=-1xx5.6=-5.6` atml L or `W=-5.6xx101.3 J=-56.28 J`.
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