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The enthalpy change for transition of li...

The enthalpy change for transition of liquid water to steam is 40.8 kJ `mol^(-1)` at 373K. Calculate `Delta S` for the process.

Text Solution

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`Delta_("vap")S=(Delta_("vap")H)/(T_(b))`
Now, `Delta_("vap")H=40.8 kJ//mol = 40800 J//mol`
`Delta_("vap")S=(40800)/(373)` or, `Delta_("vap")S=109.4 JK^(-1)mol^(-1)`
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