Calculate `Delta_(r )G` at 298 K for the following reaction if the reaction mixture consists of 1 atm of `N_(2), 3` atm of `H_(2)` and 1 atm of `NH_(3). N_(2)(g)+3H_(2)(g) hArr 2NH_(3)(g) , Delta_(r ) G^(Θ)=-33.2 kJ`

Explanation

To calculate the Gibbs free energy change (ΔG) for the given reaction at 298 K, we can use the following equation:

\[ \Delta G = \Delta G^\circ + RT \ln Q \]

### Step-by-Step Solution:

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