Calculate standard free energy change from the free energy of formation data for the following reaction, `C_(6)H_(6)(l)+(15)/(2)O_(2)(s)to 6CO_(2)(g)+3H_(2)O(g)`.
`Delta_(f)G^(theta)[C_(6)H_(6)(l)]=172.8` kJ/mol
`Delta_(f)G^(theta)[CO_(2)(g)]=-394.4` kJ/mol
Given that. `Delta_(f)G^(theta)[CO_(2)(g)]=394.4` kJ/mol
`Delta_(r )G^(theta)[H_(2)O(l)]=-228.6` kJ/mol

Explanation

To calculate the standard free energy change (ΔG°) for the reaction:

\[ C_{6}H_{6}(l) + \frac{15}{2} O_{2}(g) \rightarrow 6 CO_{2}(g) + 3 H_{2}O(g) \]

we will use the formula:

\[
\Delta G^{\circ}_{reaction} = \sum (\Delta G^{\circ}_{f, products}) - \sum (\Delta G^{\circ}_{f, reactants})
...