Home
Class 12
CHEMISTRY
Determine the heat of transformaiton of...

Determine the heat of transformaiton of `C_(("dimamond"))rarrC_(("graphite"))` form the following data:
i. `C_(("diamond"))+O_(2)(g) rarr CO_(2)(g), DeltaH^(Theta) =- 94.5 kcal`
ii. `C_(("graphite")) +O_(2)(g) rarr CO_(2)(g),DeltaH^(Theta) =- 94.0 kcal`

Text Solution

Verified by Experts

Subtracting equation (ii) from (i), the required equation is obtained, therefore ,
C(diamond) `to` C(graphite), `Delta_("trans")H=-94.5-(-94.0)=-0.5` k cal
Promotional Banner

Similar Questions

Explore conceptually related problems

Methanol can be prepared synthetically by heating carbon monoxide and hydrogen gases under pressure in the presenc eof a catalyst. The reaction is CO(g) +2H_(2)(g) rarr CH_(3)OH(l) Determine the enthalpy of this reaction by an appropriate combinantion of the following date: a. C_(("graphite")) +(1)/(2)O_(2)(g) rarr CO(g), DeltaH^(Theta)=- 110.5kJ mol^(-1) b. C_(("graphite")) +O_(2)(g) rarr CO_(2)(g), DeltaH^(Theta) =- 393.5 kJ mol^(-1) c. H_(2)(g) +(1)/(2)O_(2)(g) rarr H_(2)O(l), DeltaH^(Theta) =- 285.9kJ mol^(-1) d. CH_(3)OH(l) +(3)/(2)O_(2)(g)rarr CO_(2)(g) +2H_(2)O(l),DeltaH^(Theta) =- 726.6 kJ mol^(-1)

Calculate the heat of formation of acetic acid form the following date: a. CH_(3)COOH(l) +2O_(2)(g) rarr 2CO_(2)(g) +2H_(2)O(l)DeltaH^(Theta) =- 200.0kcal b. C(s) +O_(2) (g) rarr CO_(2)(g), DeltaH^(Theta) =- 94.0 kcal c. H_(2)(g) +(1)/(2)O_(2)(g) rarr H_(2)O(l), DeltaH^(Theta) =- 68.0 kcal

C_(("graphite")) + O_(2(g)) to CO_(2(g)) - 94.0 kcal

Calculate the enthalpy of formation of Delta_(f)H for C_(2)H_(5)OH from tabulated data and its heat of combustion as represented by the following equaitons: i. H_(2)(g) +(1)/(2)O_(2)(g) rarr H_(2)O(g), DeltaH^(Theta) =- 241.8 kJ mol^(-1) ii. C(s) +O_(2)(g) rarr CO_(2)(g),DeltaH^(Theta) =- 393.5kJ mol^(-1) iii. C_(2)H_(5)OH (l) +3O_(2)(g) rarr 3H_(2)O(g) + 2CO_(2)(g), DeltaH^(Theta) =- 1234.7kJ mol^(-1) a. -2747.1 kJ mol^(-1) b. -277.7 kJ mol^(-1) c. 277.7 kJ mol^(-1) d. 2747.1 kJ mol^(-1)

From the data at 25^(@)C : Fe_(2)O_(3)(s) +3C_(("graphite")) rarr 2Fe(s) + 3CO(g), DeltaH^(Theta) = 492.0 kJ mol^(-1) FeO(s) +C_(("graphite")) rarr Fe(s) CO(g), DeltaH^(Theta) = 155.0 kJ mol^(-1) C_(("graphite")) +O_(2)(g) rarr CO_(2)(g), DeltaH^(Theta) =- 393.0 kJ mol^(-1) CO(g)+(1)/(2)O_(2)(g) rarr CO_(2)(g), DeltaH^(Theta) =- 282.0 kJ mol^(-1) Calculate the standard heat of formation of FeSO(s) and Fe_(2)O_(3)(s) .

Calculate the DeltaH in joules for C("graphite")toC("diamond") from the following data: C("graphite")+O_(2)(g)toCO_(2)(g):" "DeltaH^(@)=-393.5kJ C("diamond")+O_(2)(g)toCO_(2)(g)," "DeltaH^(@)=-395.4kJ