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The heat liberated on complete combustio...

The heat liberated on complete combustion of `7.8g` benzene is `327kJ`. This heat has been measured at constant volume and at `27^(@)C`. Calculate heat of combustion of benzene at constant pressure at `27^(@)C`. `(R=8.3 J mol^(-1)K^(-1))`

A

`-3274 kJ`

B

`-1312 kJ`

C

`-4442 kJ`

D

`-1981 kJ`

Text Solution

Verified by Experts

`C_(6)H_(6)(l)+(15)/(2)O_(2)(g)rarr 6CO_(2)(g)+3H_(2)O(l)`
`Delta n_(g)=6-(15)/(2)=-(3)/(2)`
Also, `Delta E` per mole `=-(327xx78)/(7.8)=-3270 kJ`
Now, `Delta H = Delta E+Delta nRT`
`Delta H=-3270+(-(3)/(2))xx8.3xx300xx10^(-3) " " Delta H=-3273.735 kJ`
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