Home
Class 12
CHEMISTRY
Find out the calorific value of Glucose ...

Find out the calorific value of Glucose `C_(6)H_(12)O_(6)+6O_(2)rarr 6CO_(2)+6H_(2)O , Delta H=-2900` kJ/mole

A

33.2 kJ/g

B

16.1 kJ/g

C

13.8 kJ/g

D

9.1 kJ/g

Text Solution

Verified by Experts

Heat produced from 1 mole of `C_(6)H_(12)O_(6)(180 gm) = 2900 kJ, " "` Heat produced from 1 gm glucose `=(2900)/(180)=16.1` kJ/gm
So, calorific value of `C_(6)H_(12)O_(6)` is 16.1 kJ/gm
Promotional Banner

Similar Questions

Explore conceptually related problems

360 amu of Glucose (C_6H_12O_6) contains :

Calculate the standard Gibbs enegry change for the combustion of alpha-D glucose at 300K . C_(6)H_(12)O_(6)(s) +6O_(2)(g) rarr 6CO_(2)(g) +6H_(2)O(l) Given the standard enthalpies of formation (kJ mol^(-1)) C_(6)H_(12)O_(6) =- 1274.5, CO_(2) =- 393.5, H_(2)O =- 285.8 . Entropies (J K mol^(-1)) C_(6)H_(12)O_(6) = 212.1, O_(1) = 205.0, CO_(2) =213, H_(2)O = 69.9

Calculate the standard free energy change for the combustion of glucose at 298K, using the given data, C_(6)H_(12)O_(6)+6O_(2)to6CO_(2)+6H_(2)O DeltaH^(@)=-2820kJ" "mol^(-1),DeltaS^@=210JK^(-1)" "mol^(-1)

What is the O.N of C in C_(6)H_(12)O_(6) ?

Calculate the Delta_(r)G^(@) for the reaction: C_(6)H_(12)O_(6)(s) + 6O_(2)(g) to 6CO_(2)(g) + 6H_(2)O(l) Delta_(f)G^(@) values (kJ mol^(-1) ) are : C_(12)H_(12)O_(6)(s) = -910.2, CO_(2)(g) = -394.4, H_(2)O(l) = -237.2

According to equation, C_(6)H_(6)(l)+15//2 O_(2)(g)rarr 6CO_(2)(g)+3H_(2)O(l), Delta H= -3264.4 "KJ mol"^(-1) the energy evolved when 7.8 g benzene is burnt in air will be -