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One mole of N(2)O(4)(g) at 300 K is kept...

One mole of `N_(2)O_(4)(g)` at 300 K is kept in a closed container under one atmosphere. It is heated to 600K when 20% by mass of `N_(2)O_(4)`(g) decomposes to `NO_(2)`(g). The resultant pressure is:

A

1.2 atm

B

2.4 atm

C

2.0 atm

D

1.0 atm

Text Solution

Verified by Experts

The correct Answer is:
B
`{:(,N_(2)O_(4)(g), hArr, 2NO_(2)(g)),("Initially", 1,,0),("At equi.",(1-x),,2x):}`
Total mole at equilibrium `=1+x=1.2 " " therefore x=0.2`
`therefore (P_(1))/(n_(1)T_(1))=(P_(2))/(n_(2)T_(2)), (1)/(1xx300)=(P_(2))/(1.2xx600) or P_(2)=2.4` atm
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