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At 25^(@)C, the dissociation constant of...

At `25^(@)C`, the dissociation constant of a base. BOH is `1.0xx10^(-12)`. The concentration of hydroxyl ions in `0.01`M aqueous solution of the base would be

A

`2.0 xx 10^(-6) mol L^(-1)`

B

`1.0 xx 10^(-5) mol L^(-1)`

C

`1.0 xx 10^(-6) mol L^(-1)`

D

`1.0 xx 10^(-7) mol L^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
2
`{:(,BOH,hArr,B^(+),+,OH^(-)),("initial",C,,0,,0),("At.eq.",C-Calpha,,Calpha,,Calpha):}`
`K_(b) = (C^(2)alpha^(2))/(C(1-alpha)) = Calpha^(2) " assuming a " lt lt 1, 1 - a gt gt 1`
` 10^(-12) = 10^(-2) xx a^(2) , a^(2) = 10^(-10) , a = 10^(-5)`
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