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Calculate the pH of following solutions....

Calculate the pH of following solutions.
`N//50 HCl`

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To calculate the pH of a solution of HCl with a concentration of N/50, we can follow these steps: ### Step 1: Understand the Concentration The concentration given is N/50, which means it is 1/50 normal. Since HCl is a strong acid and dissociates completely in solution, we can also express this as molarity. \[ \text{Normality} = \text{Molarity} \times \text{n-factor} \] For HCl, the n-factor (acidity factor) is 1. Therefore, \[ \text{Molarity} = \text{Normality} = \frac{1}{50} \text{ M} = 0.02 \text{ M} \] ### Step 2: Determine the Concentration of H⁺ Ions Since HCl is a strong acid, it completely dissociates in water: \[ \text{HCl} \rightarrow \text{H}^+ + \text{Cl}^- \] Thus, the concentration of H⁺ ions will also be 0.02 M. ### Step 3: Use the pH Formula The pH is calculated using the formula: \[ \text{pH} = -\log[\text{H}^+] \] Substituting the concentration of H⁺ ions: \[ \text{pH} = -\log(0.02) \] ### Step 4: Calculate the Logarithm To calculate \(-\log(0.02)\), we can break it down: \[ \text{pH} = -\log(2 \times 10^{-2}) = -(\log(2) + \log(10^{-2})) \] We know that \(\log(10^{-2}) = -2\) and \(\log(2) \approx 0.301\). Therefore: \[ \text{pH} = - (0.301 - 2) = 1.699 \] ### Step 5: Round the pH Value Finally, we can round the pH value to one decimal place: \[ \text{pH} \approx 1.7 \] ### Final Answer The pH of the N/50 HCl solution is approximately **1.7**. ---
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