`A 0.25 ` M solution of pyridinium chloride, `C_(5)H_(5)NH^(+)Cl^(-)`, was found to have a pH of `2.89` . What is the `K_(b)` for pyridine, `C_(5)H_(5)N` ?

A 0.25 M solution of pyridinium chloride C_(5)H_(5)NH^(+)Cl^(-) was found to have a pH of 2.75 What is K_(b) for pyridine, C_(5)H_(5)N ?

A 0.25M solution of pyridinium chloride (C_(5)H_(5)overset(o+)NHC1^(Theta)) has pH of 2.89 . Calculate pK_(b) for pyridine (C_(5)H_(5)N) .

The percentage of pyridine (C_(5)H_(5)N) that forms pyridinium ion (C_(5)H_(5)N^(+)H) in a 0.10 M aqueous pyridine solution ( K_(b) for C_(5)H_(5)N=1.7xx10^(-9) ) is

Determine the pH of a 0.2 M solution of pyridine C_5H_5N. K_b= 1.5 xx 10^(-9)

What is pH of 0.02 M solution of ammonium chloride at 25^(@) C ? K_(b) (NH_(3)) = 1.8 xx 10^(-5) .

Predict the effect of addition of pyridinium ion C_5H_5NH^+ on the position of the equilibrium. Will the pH be raised or lowered ?