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Which of the following is a conjugated a...

Which of the following is a conjugated acid - base pair?

A

`HCl, NaOH`

B

`NH_(4)Cl,NH_(4)OH`

C

`H_(2)SO_(4), HSO_(4)^(-)`

D

`KCN,HCN`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given options represents a conjugate acid-base pair, we need to understand the concept of conjugate acids and bases according to the Bronsted-Lowry theory. A conjugate acid-base pair consists of two species that differ by the presence or absence of a proton (H⁺). ### Step-by-Step Solution: 1. **Understand the Definitions**: - An **acid** is a substance that donates a proton (H⁺). - A **base** is a substance that accepts a proton (H⁺). - When an acid donates a proton, it forms its **conjugate base**. - When a base accepts a proton, it forms its **conjugate acid**. 2. **Analyze Each Option**: - **Option 1: HCl and NaOH**: - HCl is an acid that donates H⁺ to form Cl⁻ (its conjugate base). - NaOH is a base that provides OH⁻ but does not form a conjugate acid from HCl. - Therefore, this is not a conjugate acid-base pair. - **Option 2: NH4Cl**: - NH4⁺ (ammonium ion) can donate a proton to form NH3 (ammonia), making NH4⁺ a conjugate acid and NH3 its conjugate base. - However, NH4Cl itself is a salt and does not represent a conjugate acid-base pair directly. - So, this is not a conjugate acid-base pair. - **Option 3: H2SO4 and HSO4⁻**: - H2SO4 (sulfuric acid) can donate a proton to form HSO4⁻ (bisulfate ion). - Here, H2SO4 is the acid, and HSO4⁻ is its conjugate base. - This is indeed a conjugate acid-base pair. - **Option 4: KCN and HCN**: - HCN (hydrogen cyanide) can donate a proton to form CN⁻ (cyanide ion), making HCN the acid and CN⁻ its conjugate base. - KCN is a salt and does not represent a conjugate acid-base pair with HCN. - Therefore, this is not a conjugate acid-base pair. 3. **Conclusion**: - The only option that represents a conjugate acid-base pair is **Option 3: H2SO4 and HSO4⁻**. ### Final Answer: **The conjugate acid-base pair is H2SO4 and HSO4⁻.**
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