The values of dissociation constants of some acids ( at `25^(@) C` are as follows. Indicate which is the strongest acid in water

Options

A. `1.4 xx 10^(-2)`
B. `1.6 xx 10^(-4)`
C. `4.4 xx 10^(-10)`
D. `4.3 xx 10^(-7)`

Answer

To determine which acid is the strongest in water based on their dissociation constants (Ka values), we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Concept of Acid Strength**:
- Acids donate protons (H⁺) to bases in aqueous solutions. The strength of an acid is determined by its ability to dissociate and release protons.

2. **Identify the Dissociation Constant (Ka)**:
- The dissociation constant (Ka) measures the extent of dissociation of an acid in water. A higher Ka value indicates a stronger acid because it means the acid dissociates more completely, releasing more H⁺ ions.

3. **Compare the Given Ka Values**:
- The problem provides several Ka values for different acids. We need to identify which of these values is the highest.
- For example, let's say the given Ka values are:
- Acid 1: \(1.4 \times 10^{-2}\)
- Acid 2: \(1.0 \times 10^{-4}\)
- Acid 3: \(1.0 \times 10^{-10}\)
- Acid 4: \(1.0 \times 10^{-7}\)

4. **Determine the Highest Ka Value**:
- Compare the Ka values:
- \(1.4 \times 10^{-2} > 1.0 \times 10^{-4} > 1.0 \times 10^{-7} > 1.0 \times 10^{-10}\)
- From this comparison, we can see that \(1.4 \times 10^{-2}\) is the highest value.

5. **Conclusion**:
- Since \(1.4 \times 10^{-2}\) is the highest Ka value, the corresponding acid is the strongest acid in water.

### Final Answer:
The strongest acid in water is the one with the dissociation constant \(1.4 \times 10^{-2}\).

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