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In a cubic lattice, the closed packed st...

In a cubic lattice, the closed packed structure of mixed oxides of the lattice is made up of oxide ion, one eight of the tetrahedral voids are occupied by divalent ions `(A^(2+))` while one half of the octahedral voids are occupied by trivalent ions `(B^(3+))` . What is the formula of the oxides?

Text Solution

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Let there be n no. of `O^(2-)` in the crystal.
`therefore` Octahedra voids = n
Tetrahedral voids = 2n
`A^(2+)"ions"=(1)/(8)xx2n=(n)/(4)," "B^(3+)"ion=(1)/(2)xxn=(n)/(2)`
`A^(2+):B^(3+):O^(2-)=(n)/(4):(n)/(2):n" "=1:2:4`
`therefore"formula is"AB_(2)O_(4)`
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