Home
Class 12
CHEMISTRY
CdO has NaCl like structure with density...

`CdO` has `NaCl` like structure with density `8.27g//c c`. If the ionic radius of `O^(2-)` is `1.24A^(@)` determine the ionic radius of `Cd^(2+)`:

Text Solution

Verified by Experts

`"Density"=(("No.of formula units")xx("Molecular weight of compound")xx1.67xx10^(-27)kg)/("Volume of unit cell")`
`8.27xx10^(3)kg//m^(3)=((4)xx128.41xx1.67xx10^(-27))/(a^3)rArra=4.70overset(@)(A)`
We have, `2[r_(Cd^(2+))+r_(O^(2-))]=a`
`rArr" "r_(Cd^(2+))+1.24=2.35" "rArr" "r_(Cd^(2+))=1.11overset(@)(A)`
Promotional Banner

Similar Questions

Explore conceptually related problems

O^(2-) and Si^(4+) are isoelectronic ions. If the ionicradius of O^(2-) is 1.4 A^(@) , the ionic radius of Si^(4+) will be

If the nuclear of radius of O^8 is 2.4 fermi, then radius of Al^27 would be

O^(2-) and Si^(4+) are isoelectronic ions. If the ionic radius of O^(2-) is 1A^(0) , the ionic radius of Si^(4+) will be

O^(2-) " and " Si^(4+) are isoelectronic ions. If the ionic radius of O^(2-) " is " 1A^(@) , the ionic radius of Si^(4+) will be

The ionic radius Na^+ ion 1.02 A^@ then ionic radius in A^@ of Mg^(2+) & Al^(3+) respectively.

Arrange the ions Na^(+), O^(2-) and F^(-) in the decreasing order of their ionic radius.

NaH crystallizes in the same structure as that of NaCl. The edge length of the cubic unit cell of NaH is 4.88 Å. (a) Calculate the ionic radius of H^(–) , provided the ionic radius of Na^(+) is 0.95 Å. (b) Calculate the density of NaH.

Casium may be considered to form interpentrating simple primitice cubic crystal. The edge length of unit cell is 412 pm. Determine a. The density of CsCl . b. The inoic radius of Cs^(o+) if the ionic radius of Cl^(Θ) is 181 pm. Given: Aw (Cs) = 133 g mol^(-1)