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The boiling point elevation contant for ...

The boiling point elevation contant for benzene is `2.57^(@)C//m`. The boiling water of benzene is `81.0^(@)C`. Determine the boiling point of a solution formed when `5 g` of `C_(14)H_(12)` is dissolved in `15 g` of benzene.

Text Solution

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Using the result :
`DeltaT_b=K_b"" (((g_B)/(M_B))/(g_A)xx1000)=2.57(((5)/(180))/(15)xx1000)=4.76^@C`
`T_b=T_b^0+DeltaT_b` [`T_b^0` = Boiling point of pure solvent]
`= 80.1+4.76 =84.86 ^@C`
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