A 0.1 M solution of potassium sulphate, `K_2SO_4` is dissolved to the extent of 90%. What would be its osmotic pressure at `27^@C` ?

Explanation

To find the osmotic pressure of a 0.1 M solution of potassium sulfate (K₂SO₄) that is dissolved to the extent of 90%, we can follow these steps:

### Step 1: Understand the formula for osmotic pressure
The osmotic pressure (π) can be calculated using the formula:
\[ \pi = i \cdot C \cdot R \cdot T \]
where:
- \( i \) = van 't Hoff factor (number of particles the solute dissociates into)
- \( C \) = molarity of the solution
...