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Calculate the boiling of one molar aqueo...

Calculate the boiling of one molar aqueous solution (density=1.04 g `mL^(-1)`) of potassium chloride `(K_(b)=0.52" K kg mol"^(-1))`

A

`107.28^@C`

B

`103.68^@C`

C

`101.078^@C`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
`m=(1000x1)/(1000xx1.-4-1xx74.5)=-1.036`
`Delta T_b =1xxX+bxxm rArr DeltaT_b =2xx0.52 xx1.036 = 1.078 rArr T_b= 101.078^@C`
(KCl is an electrolyte having n=2, `alpha=1` (if not given)
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