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The elevation in boiling point of a solu...

The elevation in boiling point of a solution of `13.44`g of `CuCl_(2)`(molecular weight =`134.4,k_(b)=0.52K "molality"^(-1))` in `1` kg water using the following information will be:

A

0.16

B

0.05

C

0.1

D

0.2

Text Solution

Verified by Experts

The correct Answer is:
A

`CuCl_2` is an electrolyte which ionise in solution as follows:

Thus, number of particles after ionization `=1-alpha +alpha+2alpha=1+alpha`
`therefore " Van't Hoff factor " (i) = ("number of praticles after ionisation")/("number of particles before ionisation") or (i) =(1+2alpha)/1 ("on" 100% "ionisation" alpha=1)`
`=(1+2xx1)/1=3`
The elevation in boiling point (when collogative property is abnormal)
`DeltaT_b =ixxK_b xxm`
m is the Molality of solution
Molality of `CuCl_2` solution = `(("Weight of"" " CuCl_2 " ""in gram")/("Mol.weight of" " "CuCl_2))/("Weight of water (Solvent) in kg ")=((13.44)/(134.4))/1=0.1m`
Thus `DeltaT_b=3xx0.52xx0.1 =0.156=0.16^@C`
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