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The vapour pressure of pure benzene at a...

The vapour pressure of pure benzene at a certain temperature is `640 mm Hg`. A non-volatile solid weighing `2.175g` is added to `39.0g` of benzene. The vapour pressure of the solution is `600mm Hg`. What is the molar mass of the solid substance?

Text Solution

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`{:(P_("Benzene")^0=640 mm Hg),(P_("sol") =600 mm Hg):}} (DeltaP )/(P_A^0)=(40)/(640)=chi_B =1/(16)=(n_B)/(n_A+n_B)=(g_B//M_B)/(g_B//M_B+g_A//M_A)`
`rArr (1)/(16)=(2.175//Mg)/(2.175//M_B+39//78)rArr M_B = 65.25gm //mol`
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