A solution containing 2.7 gm of urea per 100 ml of the solution is isotonic with a solution of sucrose. How many grams of sucrose are present in 500 mL of the solution ?

Explanation

To solve the problem, we need to determine how many grams of sucrose are present in a 500 mL solution that is isotonic with a solution containing 2.7 grams of urea per 100 mL. Here’s a step-by-step breakdown of the solution:

### Step 1: Understand the concept of isotonic solutions
Isotonic solutions have the same osmotic pressure. This means that the concentration of solute particles in both solutions must be equal.

### Step 2: Calculate the molar mass of urea
Urea has the formula \( \text{NH}_2\text{CO}\text{NH}_2 \). The molar mass of urea is calculated as follows:
- Nitrogen (N): 14 g/mol × 2 = 28 g/mol
...