Home
Class 12
CHEMISTRY
A weak electrolyte XY is 5% dissociated ...

A weak electrolyte XY is 5% dissociated in water. What is the freezing point of a 0.01 molal aqueous solution of XY ? The cryoscopic constant of water is 1.86 K/m.

Text Solution

AI Generated Solution

To solve the problem, we need to determine the freezing point of a 0.01 molal aqueous solution of the weak electrolyte XY, which is 5% dissociated in water. We'll use the cryoscopic constant of water (Kf = 1.86 K/m) and the formula for freezing point depression. ### Step-by-step Solution: 1. **Determine the degree of dissociation (α)**: Since the electrolyte XY is 5% dissociated, we can express α as: \[ \alpha = \frac{5}{100} = 0.05 ...
Promotional Banner

Similar Questions

Explore conceptually related problems

A weak electrolyte, AB, is 5% dissociated in aqueous solution. What is the freezing point of a 0.100 molal aqueous solution of AB? K_f for water is 1.86 deg/molal.

What will be the freezing point of a 0.5 m KCl solution ? The molal freezing point constant of water is 1.86^@C m^(-1) .

What will be the freezing point of 0.2 molal aqueous solution of MgBr_(2) ? If salt dissociates 40% in solution and K_(f) for water is 1.86 KKg mol^(-1)

The freezing point of a 0.05 molal solution of a non-electrolyte in water is: ( K_(f) = 1.86 "molality"^(-1) )

The freezing point of a 0.05 molal solution of a non-electrolyte in water is [K_(f)=1.86K//m]

The molal depression constant for water is 1.86^(@)C . The freezing point of a 0.05-molal solution of a non-electrolyte in water is