When acetone is added to chloroform, then hydrogen bond is formed between them.These liquids show

Options

A. Positive deviation from Raoult’s law
B. Negative deviation from Raoult’s law
C. No deviation from Raoult’s law
D. Volume is slightly increased

Answer

To solve the question regarding the behavior of acetone and chloroform when mixed, we will follow these steps:

### Step 1: Understand the Components
- **Acetone (C3H6O)**: A polar solvent with a carbonyl group (C=O) that can participate in hydrogen bonding.
- **Chloroform (CHCl3)**: A polar solvent with a hydrogen atom that can also participate in hydrogen bonding.

**Hint**: Identify the functional groups in both compounds that can form hydrogen bonds.

### Step 2: Identify the Interaction
- When acetone is mixed with chloroform, the oxygen atom in acetone can form a hydrogen bond with the hydrogen atom in chloroform. This interaction is crucial in determining the behavior of the solution.

**Hint**: Consider how hydrogen bonding affects the interactions between molecules.

### Step 3: Compare Interactions
- The interaction between acetone and chloroform (A-B interactions) is stronger than the interactions between acetone molecules (A-A) and between chloroform molecules (B-B). This is because of the formation of hydrogen bonds.

**Hint**: Think about the strength of the new interactions compared to the original interactions in pure substances.

### Step 4: Determine the Type of Solution
- Since the A-B interactions (acetone-chloroform) are stronger than the A-A and B-B interactions, this indicates that the solution will exhibit a negative deviation from Raoult's law.

**Hint**: Recall the definitions of ideal and non-ideal solutions, and how deviations from Raoult's law are categorized.

### Step 5: Conclusion
- The conclusion is that when acetone is added to chloroform, the resulting solution shows a **negative deviation from Raoult's law**. This means that the vapor pressure of the solution is lower than expected based on the mole fractions of the components.

**Hint**: Remember that negative deviation indicates stronger interactions in the mixture than in the pure components.

### Final Answer
The correct answer is that when acetone is added to chloroform, these liquids show a **negative deviation from Raoult's law**.