Identify `A,B,C,"…." ` in the given reaction sequence .
`CH_(2)BrCOOC_(2)H_(5)overset( Zn) (rarr)A underset( (ii) H_(2) O //H^(+))overset((i)"acetone")(rarr)B underset(Delta)overset(H^(+))(rarr) C`

Explanation

To identify the compounds A, B, and C in the given reaction sequence, we will analyze each step of the reaction carefully.

### Step-by-Step Solution:

1. **Starting Compound**: The starting compound is `CH₂BrCOOC₂H₅`, which is an alpha-bromo ester.

2. **Reaction with Zinc**: The first step involves the reaction of the alpha-bromo ester with zinc. This is a well-known reaction called the Reformatsky reaction. In this reaction, zinc inserts itself into the carbon-bromine bond, leading to the formation of a zinc alkoxide intermediate.
- **Product A**: The product after this step (A) will be `CH₂(ZnBr)COOC₂H₅`, which can be represented as `CH₂COOC₂H₅` with a zinc atom replacing the bromine.
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