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Which of the following gives aldol conde...

Which of the following gives aldol condensation reaction ?

A

`C_(6)H_(5)OH`

B

`C_(6)H_(5)-CO-C_(6)H_(5)`

C

2-Butanone

D

3,3-dimethyl 2-butanone

Text Solution

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The correct Answer is:
To determine which of the given compounds undergoes aldol condensation, we need to follow these steps: ### Step 1: Understand Aldol Condensation Aldol condensation is a reaction that occurs between aldehydes or ketones that have at least one alpha-hydrogen in the presence of a dilute alkali base (like sodium hydroxide or potassium hydroxide). The reaction results in the formation of β-hydroxy aldehydes or ketones, which can further dehydrate to give α,β-unsaturated carbonyl compounds. ### Step 2: Identify the Compounds We have four options to analyze: 1. **C6H5OH** (Phenol) 2. **C6H5** (Benzene) 3. **2-butanone** (CH3COCH2CH3) 4. **3,3-dimethyl-2-butanone** (CH3C(=O)C(CH3)2CH3) ### Step 3: Analyze Each Compound - **Option 1: C6H5OH (Phenol)** - Phenol is an alcohol and does not contain an aldehyde or ketone functional group. Therefore, it cannot undergo aldol condensation. - **Option 2: C6H5 (Benzene)** - Benzene is a hydrocarbon and does not have a functional group that can participate in aldol condensation. It lacks both carbonyl and alpha-hydrogens. Thus, it cannot undergo aldol condensation. - **Option 3: 2-butanone (CH3COCH2CH3)** - 2-butanone has the structure: ``` CH3-CO-CH2-CH3 ``` The carbon adjacent to the carbonyl (C=O) has two alpha-hydrogens (the CH2 group). Therefore, it can undergo aldol condensation. - **Option 4: 3,3-dimethyl-2-butanone (CH3C(=O)C(CH3)2CH3)** - The structure is: ``` CH3-C(=O)-C(CH3)2-CH3 ``` Although it has alpha-hydrogens, steric hindrance due to the bulky methyl groups on the alpha carbon prevents it from undergoing aldol condensation effectively. ### Step 4: Conclusion Based on the analysis, the only compound that can undergo aldol condensation is **2-butanone** (Option 3). ### Final Answer: **2-butanone (Option 3) gives aldol condensation reaction.** ---
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