Hydrolysis of `CH_(3)CH_(2)NO_(2)` with 85% `H_(2)SO_(4)` gives `:`

Options

A. `CH_(3)CH_(2)OH`
B. `C_(2) H_(6)`
C. `CH_(3)CH=NOH`
D. `CH_(3)COOH`

Answer

To solve the question regarding the hydrolysis of `CH3CH2NO2` with 85% `H2SO4`, we will follow these steps:

### Step 1: Understand the Structure of `CH3CH2NO2`
The compound `CH3CH2NO2` is ethyl nitro compound. The structure can be represented as follows:
```
CH3-CH2-NO2
```
In this structure, the `NO2` group is attached to the ethyl group.

### Step 2: Reaction with `H2SO4`
When `CH3CH2NO2` is treated with concentrated sulfuric acid (85% `H2SO4`), it acts as a strong acid and can facilitate the hydrolysis of the nitro group. The sulfuric acid will protonate the nitro group, making it more electrophilic.

### Step 3: Formation of an Intermediate
The protonation of the nitro group leads to the formation of a positively charged intermediate. The reaction can be visualized as:
```
CH3-CH2-NO2 + H+ → CH3-CH2-NO2H+
```
This intermediate can then undergo nucleophilic attack by water.

### Step 4: Nucleophilic Attack by Water
Water acts as a nucleophile and attacks the positively charged nitrogen in the intermediate:
```
CH3-CH2-NO2H+ + H2O → CH3-CH2-N(OH)2 + H+
```
This results in the formation of a hydroxylamine derivative.

### Step 5: Elimination of Water
The hydroxylamine derivative can lose a molecule of water, leading to the formation of an aldehyde:
```
CH3-CH2-N(OH)2 → CH3-CHO + H2O
```
Here, `CH3-CHO` is acetaldehyde.

### Step 6: Final Product
The final product after the hydrolysis of `CH3CH2NO2` with `H2SO4` is acetaldehyde (`CH3CHO`).

### Conclusion
Thus, the hydrolysis of `CH3CH2NO2` with 85% `H2SO4` gives acetaldehyde (`CH3CHO`).