Laboratory method for the preparation of acetyl chloride is `:`

Options

A. `CH_(3)COOH+SOCl_(2) rarr CH_(3)COCl+SO_(2)+HCl`
B. `CH_(3)COOH+PCl_(3) rarrCH_(3)COCl`
C. `CH_(3)COONa+PCl_(3) rarr CH_(3) COCl`
D. All of these

Answer

To prepare acetyl chloride in the laboratory, we can use the following method:

### Step-by-Step Solution:

1. **Identify the Reactants**: The primary reactants for the preparation of acetyl chloride (CH3COCl) are acetic acid (CH3COOH) and thionyl chloride (SOCl2).

2. **Write the Reaction**:
The reaction can be represented as:
\[ \text{CH}_3\text{COOH} + \text{SOCl}_2 \rightarrow \text{CH}_3\text{COCl} + \text{SO}_2 + \text{HCl} \]
Here, acetic acid reacts with thionyl chloride to produce acetyl chloride, sulfur dioxide (SO2), and hydrogen chloride (HCl).

3. **Reaction Conditions**: The reaction is typically carried out under mild conditions. It is advisable to perform this reaction in a fume hood due to the release of gases (SO2 and HCl).

4. **By-products Handling**: Since SO2 and HCl are gaseous by-products, they will escape from the reaction mixture, making this method safer and more manageable in a laboratory setting.

5. **Final Product**: The product of the reaction is acetyl chloride, which can be collected and purified if necessary.

### Conclusion:
The laboratory method for the preparation of acetyl chloride is by reacting acetic acid with thionyl chloride.

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