The product D of the reaction `CH_(3)Cl overset( KCN) ( rarr) ( A) overset( H_(2) O) ( rarr) (B) overset( NH_(3))(rarr) ( C ) overset( Delta)( rarr) ( D ) ` is

Options

A. `CH_(3)CH_(2)NH_(2)`
B. `CH_(3)CN`
C. `HCONH_(2)`
D. `CH_(3)CONH_(2)`

Answer

To determine the product D of the given reaction sequence, we will analyze each step of the reaction systematically.

### Step-by-Step Solution:

1. **Reaction of Methyl Chloride with Potassium Cyanide (KCN)**:
- Methyl chloride (CH₃Cl) reacts with potassium cyanide (KCN) through an SN2 mechanism. The cyanide ion (CN⁻) acts as a nucleophile and attacks the carbon atom in methyl chloride, resulting in the substitution of the chlorine atom.
- **Product A**: CH₃CN (methyl cyanide or acetonitrile) + KCl

2. **Hydrolysis of Product A (CH₃CN) with Water (H₂O)**:
- The acetonitrile (CH₃CN) undergoes hydrolysis when treated with water. The triple bond between carbon and nitrogen is broken, and water adds across the bond, resulting in the formation of acetic acid (CH₃COOH) and ammonia (NH₃).
- **Product B**: CH₃COOH (acetic acid) + NH₃

3. **Reaction of Product B (Acetic Acid) with Ammonia (NH₃)**:
- Acetic acid (CH₃COOH) reacts with ammonia (NH₃). In this reaction, the ammonia acts as a base and accepts a proton from the acetic acid, leading to the formation of ammonium acetate (CH₃COO⁻NH₄⁺).
- **Product C**: CH₃COO⁻NH₄⁺ (ammonium acetate)

4. **Heating of Product C (Ammonium Acetate)**:
- When ammonium acetate (CH₃COO⁻NH₄⁺) is heated, it undergoes a dehydration reaction, where water is eliminated, resulting in the formation of an amide.
- **Product D**: CH₃CONH₂ (ethanamide or acetamide) + H₂O

### Final Answer:
The product D of the reaction sequence is **CH₃CONH₂ (ethanamide)**.

---