o-oxylene when oxidised in presence of `V_(2)O_(5)` the product is `:`

Options

A. Benzoic acid
B. Phenyl acetic acid
C. Phthalic acid
D. Acetic acid

Answer

To solve the question regarding the oxidation of o-oxylene in the presence of V2O5, we will follow these steps:

### Step 1: Identify the structure of o-oxylene
o-Oxylene, also known as ortho-xylene, has the following structure:
- It consists of a benzene ring with two methyl groups (CH3) attached to adjacent carbon atoms (ortho position).

**Structure of o-oxylene:**
```
CH3
|
C6H4
|
CH3
```

### Step 2: Understand the oxidation process
When o-oxylene is oxidized, the methyl groups (–CH3) can be converted into carboxylic acid groups (–COOH). The oxidizing agent used here is V2O5, which is a strong oxidizer.

### Step 3: Reaction with V2O5
During the oxidation process, o-oxylene undergoes a reaction where both methyl groups are oxidized to form a dicarboxylic acid. The product formed is phthalic acid (1,2-benzenedicarboxylic acid).

**Reaction:**
```
C6H4(CH3)2 + O (from V2O5) → C6H4(COOH)2
```

### Step 4: Final product
The final product of the oxidation of o-oxylene in the presence of V2O5 is phthalic acid.

**Structure of phthalic acid:**
```
COOH
|
C6H4
|
COOH
```

### Conclusion
Thus, the product formed when o-oxylene is oxidized in the presence of V2O5 is **phthalic acid**.