When chlorobenzene is treated with `NH_(3)` in presence of `Cu_(2)O` in xylene is 570 K. The product obtained is

Options

A. Benzylamine
B. Diazonium salt
C. Schiff's base
D. Aniline

Answer

To solve the question regarding the reaction of chlorobenzene with ammonia in the presence of Cu₂O and xylene at a temperature of 570 K, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are chlorobenzene (C₆H₅Cl) and ammonia (NH₃). The presence of Cu₂O (copper(I) oxide) acts as a catalyst in this reaction.

2. **Understand the Reaction Conditions**:
- The reaction is conducted in xylene, which is a solvent that can help dissolve the reactants and facilitate the reaction. The temperature of 570 K is relatively high, which can promote the reaction.

3. **Mechanism of the Reaction**:
- Chlorobenzene contains a chlorine atom that is a good leaving group. When ammonia is present, it can attack the carbon atom bonded to chlorine.
- The chlorine atom leaves as chloride ion (Cl⁻), and the nitrogen atom from ammonia (NH₃) replaces it, forming an amine.

4. **Formation of the Product**:
- The product formed from this reaction is aniline (C₆H₅NH₂). The reaction can be summarized as:
\[ \text{C}_6\text{H}_5\text{Cl} + \text{NH}_3 \xrightarrow{\text{Cu}_2\text{O}, \text{xylene}, 570 \text{ K}} \text{C}_6\text{H}_5\text{NH}_2 + \text{Cu}_2\text{Cl}_2 + \text{H}_2\text{O} \]
- Here, aniline is the desired product, along with copper(I) chloride (Cu₂Cl₂) and water (H₂O) as by-products.

5. **Conclusion**:
- The product obtained from the reaction of chlorobenzene with ammonia in the presence of Cu₂O and xylene at 570 K is aniline.

### Final Answer:
The product obtained is **aniline (C₆H₅NH₂)**.

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