Evaluate differentiation of y with respect to x.
`(3x+cotx)`

Explanation

To evaluate the differentiation of \( y \) with respect to \( x \) for the function \( y = 3x + \cot x \), we will follow these steps:

### Step-by-Step Solution:

1. **Identify the function**:
\[ y = 3x + \cot x \]
Here, we have two terms: \( 3x \) (an algebraic term) and \( \cot x \) (a trigonometric term).

2. **Differentiate each term separately**:
- For the first term \( 3x \):
- The differentiation of \( 3x \) with respect to \( x \) is:
\[ \frac{d}{dx}(3x) = 3 \]
- For the second term \( \cot x \):
- The differentiation of \( \cot x \) is:
\[ \frac{d}{dx}(\cot x) = -\csc^2 x \]
(where \( \csc x \) is the cosecant function).

3. **Combine the results**:
- Now, we can combine the results of the differentiation:
\[ \frac{dy}{dx} = \frac{d}{dx}(3x) + \frac{d}{dx}(\cot x) = 3 - \csc^2 x \]

4. **Final result**:
\[ \frac{dy}{dx} = 3 - \csc^2 x \]

### Summary:
The differentiation of \( y \) with respect to \( x \) is:
\[ \frac{dy}{dx} = 3 - \csc^2 x \]