Find out the angle made by `vecA= hati+hatj+hatk` vector from X, Y and Z axes respectively.

Answer

`cos^(-1).(1)/(sqrt(3))`

Explanation

Given `A_(x)=A_(y)=A_(z)=1`
`A=sqrt(A_(x)^(2)+A_(y)^(2)+A_(z)^(2))=sqrt(1+1+1)=sqrt(3)`
`cosalpha=(A_(x))/(A)=(1)/(sqrt(3))oralpha=cos^(-1).(1)/(sqrt(3)),cosbeta=(A_(y))/(A)=(1)/(sqrt(3))orbeta=cos^(-1).(1)/(sqrt(3))`
`cosgamma=(A_(z))/(A)=(1)/(sqrt(3))or gamma=cos^(-1).(1)/(sqrt(3))`