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A force is inclined at an angle of 60^(@...

A force is inclined at an angle of `60^(@)` from the horizontal. If the horizontal component of the force is 40N,calculate the vertical component.

Text Solution

Verified by Experts

The correct Answer is:
`69.28N`
`A_(x)=40N, A_(y)=?, theta=60^(@)`
`A_(x)=Acostheta therefore 40=Acos60^(@)=(A)/(2)orA=80N`
Now `A_(y)=Asin60^(@)=(Asqrt(3))/(2)=(80sqrt(3))/(2)=40sqrt(3)=40xx1.732=69.28N`
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