Home
Class 12
PHYSICS
what is the dot product of two vectors o...

what is the dot product of two vectors of magnitudes 3 and 5,if angle between them is `60^@`?

Text Solution

Verified by Experts

Here `P=5`
`Q=3 theta=60^(@)`
`R=sqrt(P^(2)+Q^(2)+2PQcostheta)=sqrt(5^(2)+3^(2)+2.5.3cos60^(@))=7` units
`sinalpha=(Qsintheta)/(R)=(3)/(2)sin60^(@)=(3sqrt3)/(14)`
Promotional Banner

Similar Questions

Explore conceptually related problems

What is the dot product of two vectors of magnitude 3 and 5, if the angle between them is 60^(@) ?

The magnitude of the resultant of two vectors of magnitudes 5 and 3 is 2. What is the angle between the two vectors ?

Let veca and vecb be two vectors of the same magnitude such that the angle between them is 60^(@) and veca.vecb =8. Find |veca| and |vecb| .

The dot product of two vectors of magnitudes 3 units and 5 units cannot be :- (i) -20 (ii) 16 (iii) -10 (br) 14

Square of the resultant of two forces of equal magnitude is equal to three times the product of their magnitude. The angle between them is

Square of the resultant of two forces of equal magnitude is equal to three times the product of their magnitude. The angle between them is :

Square of the resultant of two forces of equal magnitude is equal to three times the product of their magnitude. The angle between them is

For the resultant of two vectors to be maximum , what must be the angle between them ?

A resultant of 60 N is produced due to two forces having magnitudes in the ratio 4:5 Calculate the magnitude of each if the angle between them is 30^(@)