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There are two vectors vecA= 3hati+hatj ...

There are two vectors `vecA= 3hati+hatj and vecB=hatj+2hatk`. For these two vectors -
(a) If `vecA & vecB` are the adjacent sides of a parallelogram then find the magnitude of its area.
(b) Find a unit vector which is perpendicular to both `vecA & vecB`.

Text Solution

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Area of the parallelogram `=|vecAxxvecB|=|(hati,hatj,hatk),(3,1,0),(0,1,2)|=|2hati-6hatj+3hatk|=sqrt(2^(2)+(-6)^(2)+3^(2))=7` units
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