The original length of wire is (153.7 pm...

The original length of wire is `(153.7 pm 0.6) cm`. It is streched to `(155.3 pm 0.2)` cm. Calculate the elongation in the wire with error limits.

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Elongation `(l)=155.3-153.7=1.6cm`
`Deltal=pm (Deltal_(1)+Deltal_(2))`
`=pm(0.6+0.2)=pm 0.8cm.`
`therefore" Elongation "=(1.6pm0.8)cm`

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