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An experiment measures quantities a, b a...

An experiment measures quantities a, b and c and X is calculated from `X= ab^(2)//c^(3)`. If the percentage error in a, b and c are `pm 1%, pm 3% and pm 2%` respectively, the percentage error in X will be-

A

`13%`

B

`12%`

C

`11%`

D

`10%`

Text Solution

Verified by Experts

The correct Answer is:
A
Here, `(Deltaa)/(a)xx100 pm 1%, (Deltab)/(b)xx100=pm 3%, (Deltac)/(c )xx100=pm 2%`
`x=(ab^(2))/(c^(3))`
Maximum percentage error in x is `(Deltax)/(x)xx100=(Deltaa)/(a)xx100+2(Deltab)/(b)xx100+3(Deltac)/(c )xx100=1+(2xx3)+(3xx2)=13%`
Maximum percentage error is x is `13%`.
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