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The numerical values and units of a phys...

The numerical values and units of a physical quantity in two different system of units are `n_(1), n_(2) and u_(1), u_(2)` respectively. Then

A

`n_(1)u_(2)=n_(2)u_(1)`

B

`n_(1)u_(1)^(2)=n_(2)u_(2)^(2)`

C

`n_(1)=n_(2) & u_(1)=u_(2)`

D

`n_(1)u_(1)=n_(2)u_(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to understand the relationship between the numerical values and units of a physical quantity in two different systems of units. ### Step-by-Step Solution: 1. **Understanding the Physical Quantity**: - A physical quantity can be expressed as the product of a numerical value and a unit. This can be represented as: \[ PQ = n \cdot u \] - Where \( PQ \) is the physical quantity, \( n \) is the numerical value, and \( u \) is the unit. 2. **Setting Up the Equation**: - For two different systems of units, we have: - In the first system: \( n_1 \) and \( u_1 \) - In the second system: \( n_2 \) and \( u_2 \) - Therefore, we can write: \[ n_1 \cdot u_1 = n_2 \cdot u_2 \] 3. **Understanding the Relationship**: - This equation indicates that the product of the numerical value and the unit remains constant when switching between different units for the same physical quantity. - This means that if you change the unit, the numerical value will change in such a way that their product remains the same. 4. **Conclusion**: - Thus, we can conclude that: \[ n_1 \cdot u_1 = n_2 \cdot u_2 \] - This relationship shows that if one unit is larger, the corresponding numerical value will be smaller, and vice versa. ### Final Answer: \[ n_1 \cdot u_1 = n_2 \cdot u_2 \] ---
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