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If acos theta-b sin theta=c , show that...

If `acos theta-b sin theta=c ,` show that `asin theta+b cos theta=+-sqrt(a^2+b^2+c^2dot)`

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Given that `a {co} \theta-b \sin \theta=c`
Squaring both the sides, we have,
`(a \cos \theta-b \sin \theta)=c^{2} `
`\Rightarrow a^{2} \cos ^{2} \theta+b^{2} \sin ^{2} \theta-2 a b \cos \theta \sin \theta=c^{2} `
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