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SiCl(4) on hydrolysis forms 'X' and HCl....

`SiCl_(4)` on hydrolysis forms 'X' and HCl. Compound 'X' loses water at `1000^(@)C` and gives 'Y' compounds 'X' and 'Y' respectively are

A

`H_(2)SiCl_(6),SiO_(2)`

B

`H_(4)SiO_(4),Si`

C

`SiO_(2),Si`

D

`H_(4)SiO_(4), SiO_(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
`SiCl_(4)+4H_(2)O to H_(4)SiO_(4)+4HCl`
`H_(4)SiO_(4) underset(1000^(@)C)overset(Delta)to SiO_(2)+2H_(2)O`
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