Chlorine is passed into dilute cold KOH solution. What are the oxidation numbers of chlorine in the products formed ?

Options

A. `-1,+5`
B. `-1,+3`
C. `+1,+7`
D. `-1,+1`

Answer

D

Explanation

The reaction is as follows,
`2KOH + Cl_(2) to KCl +KOCl +H_(2)O` Oxidation number of chlorine in KCl and KOCl is
`{:("In KCl","In KOCl"),((+1)+x=0,1-2+x=0),(thereforex=-1,therefore x=+1):}`