1 L of oxygen at a pressure of 1 atm and 2 L of nitrogen at a pressure of 0.5 atm, are introduced into a vessel of volume 1 L. If there is no change in temperature, the final pressure of the mixture of gas (in atm) is

Options

A. 1.5
B. 2.5
C. 2
D. 4

Answer

C

Explanation

pV=nrT
For Oxygen,
`1xx1=n_(0)=1/(RT)`
For nitrogen,
`0.5xx2=n_(N)RT`
`therefore n_(N)=1/(RT)`
For a mixture,
`P_(t otal)V_(t otal)=n_(t otal) . RT=(n_(o) + n_(N))RT`
`=(1/(RT) + 1/(RT)) RT`
`therefore p_(t otal)V_(t otal)=2`