A horizontal pipe of non-uniform cross-section allows water to flow through it wwith a velocity `1ms^-1` when pressure is 50 kPa at a point. If the velocity of flow has to be `2ms^-1` at some other point, the pressure at that point should be

Options

A. 50kPa
B. 100kPa
C. 48.5kPa
D. 24.25kPa

Answer

C

Explanation

`P_(1) + 1/2 rhoV_(1)^(2)= P_(2) + 1/2 rhoV_(2)^(2)`
[Bernoulli's equationfor horizontal pipes ]
`P_(2)=P_(1) + 1/2 rho (V_(1)^(2)-V_(2)^(2))`
`=50 xx 10^(3) + 1/2xx10^(3)xx(1^(2) - 2^(2))`
`therefore P_(2)=48.5 kPa`