The tyre of a motor car contains air at `15^@C`. If the temperature increases to `35^@C` , the approximate percentage increase in pressure is (ignore expansion of tyre)

Options

A. 7
B. 9
C. 11
D. 13

Answer

A

Explanation

`T_(1) = 15 + 273 = 288K`
`T_(2) = 35 + 273 = 308K`
`P_(1)/T_(1) = P_(2)/ T_(2)` [`because ` Volume is constant]
`P_(1)/P_(2)=T_(1)/T_(2) = 288/308`
Percentage increase in pressure,
`= (P_(2)-P_(1))P_(1) xx100 = (308-288)/288 xx100 cong 7%`