A water barrel having water upto a depth d is placed on a table of height h. A small hole is made on the wall of barrel at its bottom. If the stream of water coming out of the hole falls on the ground at a horizontal distance R from the barrel, then the value of d is

Options

A. `(4h)/R^2`
B. `4hR^2`
C. `R^(2)/(4h)`
D. `h/(4R^(2))`

Answer

C

Explanation

Horizontal range, R= Velocity `xx` Time
`=sqrt(2gd) xx sqrt((2h)/g)`
`R^(2) = 2gd xx (2h)/g = 4dh`
`therefore d=R^(2)/(4h)`