The mass of oxygen gas ocçupying a volume of 11.2 L at a temperature `27^@`C and a pressure of 760 mm of mercury in kilogram is [Molecular weight of oxygen = 32]

Options

A. 0.001456
B. 0.01456
C. 0.1456
D. 1.1456

Answer

B

Explanation

`(P_(1)V_(1))/(m_(1)T_(1)) = (P_(2)V_(2))/(m_(2)T-(2))`
Mass of oxygen at STP = 32g
`(760xx22.4)/(32xx273) = (760xx11.2)/(m_(2)xx300) = 14.56`
`therefore m_(2) = 0.01456 kg`